Skip to main content

Programming

Search Here for Solutions

Learn laravel

November 18, 2019

Get link
Facebook
Twitter
Pinterest
Email
Other Apps

Learn laravel from basics to advanced. Laravel tutorials and blog. Easy tutorials at here https://russelltheprogrammer.com/category/laravel/

LARAVEL FOR BEGINNERS

Get link
Facebook
Twitter
Pinterest
Email
Other Apps

Hello , i am REZIAL. Nice to meet you....

Comments

Post a Comment

Thanks for your message

IMPORTANT TUTORIALS

URI ONLINE JUDGE :: 2344 - Notas da Prova Solution in C++

URI Online Judge | 2344 Notas da Prova problem details: https://www.urionlinejudge.com.br/judge/en/problems/view/2344 Solution In C++; #include <bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; if(n==0) cout<<"E"<<endl; else if(n>=1 && n<=35) cout<<"D"<<endl; else if(n>=36 && n<=60) cout<<"C"<<endl; else if(n>=61 && n<=85) cout<<"B"<<endl; else if(n>=86 && n<=100) cout<<"A"<<endl; return 0; }

Top 50 Dynamic Programming Practice Problems

Top 50 Dynamic ProgramPractice Problems Source: https://blog.usejournal.com/top-50-dynamic-programming-practice-problems-4208fed71aa3 Get started Top 50 Dynamic Programming Practice Problem Dynamic Programming is a method for solving a complex problem by breaking it down into a collection of simpler subproblems, solving each of those subproblems just once, and storing their solutions using a memory-based data structure (array, map,etc). Each of the subproblem solutions is indexed in some way, typically based on the values of its input parameters, so as to facilitate its lookup. So the next time the same subproblem occurs, instead of recomputing its solution, one simply looks up the previously computed solution, thereby saving computation time. This technique of storing solutions to subproblems instead of recomputing them is called memoization. Here’s brilliant explanation on concept of Dynamic Programming on Quora — Jon

URI Online Judge | 2552 CheeseBreadSweeper solution in C++

< Try yourself first > problem details: https://www.urionlinejudge.com.br/judge/en/problems/view/2552 Solutions in C++: #include<bits/stdc++.h> using namespace std; int main() { int N,M; while(cin>>N>>M) { int a[N][M]; for(int i=0;i<N;i++) { for(int j=0;j<M;j++) cin>>a[i][j]; } if(M==1) { if(N==1) { if(a[0][0]==1) cout<<9<<endl; else cout<<0<<endl; } else{ for(int i=0;i<N;i++) { int sum=0; if(i!=N-1) { if(a[i][0]==1) cout<<9<<endl; else { if(a[i+1][0]==1) sum+=1;

URI Online Judge 1189 - Left Area Solve #solution #coding #uri

Solution of URI 1189 :: Left Area ~Try Yourself First uri 1189 - uri 1189 solution || URI problem 1182 solution in C | (Column in Array) - Code , || 2060 - Problem - solve - Code: uri , Solution of URI 1182 :: Column in Array ~try Yourself first , 1189 - Left Area Solve #solution #coding #uri - URI Online Judge uri 1189 solution uri 1189 solution in c www uri uri problem solution uri o uri online judge3 uri program uri academic

URI 1985 problem solve in c++

problem details: https://www.urionlinejudge.com.br/judge/en/problems/view/1985 Solution in C++: #include <iostream> #include <iomanip> using namespace std; int main() { int a;double sum=0.0; cin>>a; for(int b=1;b<=a;b++){ int c,d; cin>>c>>d; if(c==1001){ sum=sum+(d*1.50); } else if(c==1002){ sum=sum+(d*2.50); } else if(c==1003){ sum=sum+(d*3.50); } else if(c==1004){ sum=sum+(d*4.50); } else if(c==1005){ sum=sum+(d*5.50); } } cout << fixed<<setprecision(2)<<sum << endl; return 0; }

Powered by Blogger

ALL RIGHTS RESERVED BY programmingsolutionseasy.blogspot.com